Finding 3x-y: A Deep Dive Into Matrix Transpose

by Dimemap Team 48 views

Hey math enthusiasts! Let's dive into a cool matrix problem. We've got two matrices, AA and BB, and a condition: AA equals the transpose of BB (written as BTB^T). Our mission? To find the value of 3xβˆ’y3x - y. Sounds like fun, right?

Understanding the Problem: Matrix Transpose and Equality

First off, let's break down the core concepts. Matrices are rectangular arrays of numbers. Matrix AA is given as (2x63βˆ’2)\begin{pmatrix} 2x & 6 \\ 3 & -2 \end{pmatrix} and matrix BB is (4312yβˆ’2)\begin{pmatrix} 4 & 3 \\ 12y & -2 \end{pmatrix}. The key here is the transpose. The transpose of a matrix is obtained by interchanging its rows and columns. So, if we have a matrix, like our BB, its transpose (BTB^T) is what we get when we flip its rows into columns (or vice versa). Think of it like rotating the matrix 90 degrees.

Since we're told that A=BTA = B^T, it means every element in matrix AA must be equal to the corresponding element in the transpose of BB. This is crucial. It gives us a way to build a set of equations to solve for our unknowns, xx and yy. This concept is the heart of the problem, and understanding it makes the rest of the solution a breeze. The equality of matrices is a fundamental concept in linear algebra, and it allows us to create a system of equations. These equations will then help us to find the values of x and y, eventually leading us to calculate 3xβˆ’y3x - y. Remember, the position of each element matters. The element in the first row and first column of AA must equal the element in the first row and first column of BTB^T, and so on. Let's get our hands dirty by applying this idea to our specific matrices. This ensures we are on the right track and haven't missed any essential steps in understanding the problem. Understanding the transpose is key, and the equation A=B^T unlocks everything.

Now, let's consider the individual elements, the numbers, within the matrices. The elements must be equal if A = B^T. This is where we bring the x and y into the picture. Every component must be equal. It means we're going to create equations to solve for our variables. Are you with me?

We start by recognizing that A=BTA = B^T. This simple statement provides a powerful foundation for solving the problem. The transpose operation is fundamental, swapping rows with columns. With this in mind, the process becomes rather straightforward. Are you ready? Let's get to the calculations!

Step-by-Step Solution: Unveiling x and y

Okay, guys, let's find the solution step by step. Here’s how we'll solve this: We know A=(2x63βˆ’2)A = \begin{pmatrix} 2x & 6 \\ 3 & -2 \end{pmatrix} and B=(4312yβˆ’2)B = \begin{pmatrix} 4 & 3 \\ 12y & -2 \end{pmatrix}. We're also told that A=BTA = B^T. This means we need to find the transpose of BB, which is BT=(412y3βˆ’2)B^T = \begin{pmatrix} 4 & 12y \\ 3 & -2 \end{pmatrix}. See how we swapped the rows and columns? Easy peasy!

Now, we equate the corresponding elements of AA and BTB^T: * 2x=42x = 4 * 6=12y6 = 12y * 3=33 = 3 * βˆ’2=βˆ’2-2 = -2

From the first equation, 2x=42x = 4, we find that x=2x = 2. From the second equation, 6=36 = 3, we find that 12y=612y = 6, so y=1/2y = 1/2. Now we've got the values for both xx and yy! The next step involves calculating the value we actually want: 3xβˆ’y3x - y. The beauty of this process is that by setting up the right equations, the solution reveals itself.

Let's clarify the logic. We've got our matrices, we understand the transpose concept, and we've set up the necessary equations. This allows us to find the values of the variables we need. Every step is related to the fundamental idea of matrix equality, which is derived from the original equation. We take the time to arrange everything logically. The structure we follow ensures clarity and efficiency in problem-solving. This problem is not just about calculations, it’s about a methodical approach. We are almost there, keep the focus!

This methodical approach underscores the underlying principles of solving matrix problems. Understanding the conditions given to us is of utmost importance. Let us analyze how to efficiently find xx and yy values, since it is a crucial part of the process. We will get the values, and the last thing to do is to find out the value of 3xβˆ’y3x - y.

Calculating 3x - y: The Final Countdown

Alright, we're in the final stretch! We've found that x=2x = 2 and y=1/2y = 1/2. Now, we simply plug these values into the expression 3xβˆ’y3x - y: 3xβˆ’y=3(2)βˆ’(1/2)=6βˆ’1/2=5.53x - y = 3(2) - (1/2) = 6 - 1/2 = 5.5.

So, the value of 3xβˆ’y3x - y is 5.5! That’s it, we’ve solved the problem. It wasn’t that hard, right? The key was understanding the transpose operation and setting up those equations correctly. This final step is straightforward, simply involving the substitution of known values into the target expression. This is where we bring everything together, applying the values we found earlier to get our final answer. It wraps up the process, bringing us full circle. This is the moment to celebrate your successful calculations! Remember, practice makes perfect. The more you work with matrices, the easier these problems become.

The calculation confirms our understanding, and we've got the final solution. Matrix problems can seem daunting at first, but by systematically breaking them down, they become solvable. You can apply the same logic to other matrix problems and become a pro! We started with two matrices, applied the concept of the transpose, and solved for our final answer, 3xβˆ’y3x - y. The satisfaction of getting the correct result comes from careful reasoning.

By staying organized and sticking to a strategic approach, these kinds of problems become easier. Remember to always double-check your work, and don't hesitate to ask for help when you need it. This whole process, from the initial setup to the final calculation, demonstrates the beauty and power of linear algebra in solving real-world problems. Great job, everyone!

Conclusion: Mastering Matrix Operations

So, what have we learned, friends? We've successfully navigated the world of matrix transposes and solved for 3xβˆ’y3x - y. The key takeaways from this exercise are understanding how to find a matrix transpose, knowing how to set up equations from matrix equality, and how to solve for unknown variables.

This problem isn’t just about the numbers; it’s about the process. We practiced the fundamental rules of matrices. These techniques are applicable in various fields like computer graphics, data analysis, and even physics. By understanding these concepts, you're not just solving a math problem, you're building a foundation for more advanced topics. Remember, the effort we've put in to solve this problem can be transferred to any other problem. Practice by varying the matrix elements, the given expressions and conditions. This approach will deepen your understanding and enhance your problem-solving skills.

Keep practicing! The more problems you solve, the more comfortable you'll become with matrices. Keep your curiosity alive. With each problem you solve, you'll become more confident in your abilities. Remember to review your work and learn from any mistakes. Matrix problems aren't just about finding solutions; they're about building a strong mathematical foundation. You've got this!