Finding F(x): A Step-by-Step Guide For Math Enthusiasts

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Hey math lovers! Today, we're diving into a fun problem involving function composition. We're given two functions, ff and gg, and we know how they behave when combined. Our mission? To uncover the mystery of the function f(x)f(x). Don't worry; it's easier than it sounds! We'll break down the problem step by step, making sure everyone can follow along. Let's get started, shall we?

Understanding the Problem: Unveiling Function Composition

So, what exactly are we dealing with? We're given that (f∘g)(x)=8x3βˆ’20x2+22xβˆ’10(f \circ g)(x) = 8x^3 - 20x^2 + 22x - 10 and g(x)=2xg(x) = 2x. The notation (f∘g)(x)(f \circ g)(x) represents function composition, which means we're applying function gg first and then applying function ff to the result. Think of it like a chain reaction: you input a value into gg, and its output becomes the input for ff. Our ultimate goal is to figure out what f(x)f(x) looks like on its own. It's like finding the hidden treasure by following a series of clues. Understanding this concept is crucial. Function composition is when you apply one function to the result of another function. The given problem uses this to obfuscate the process of finding the underlying function. The power of composition lies in its ability to create complex relationships from simpler ones. In this case, we have a relatively complex polynomial resulting from the composition of f and g. Our strategy will be to work backward, unraveling the layers to reveal the function f(x)f(x). We have the composite function and the inner function, so our task becomes one of reverse engineering. We will delve deeper into each step to ensure that even those new to function composition can understand. Now, let's explore this step-by-step.

Step 1: Recognizing the Inner Function and Composite Function

The first key to solving this is to clearly identify what we have. We know the result of applying g(x)g(x) first, and then applying ff to that result. Let's start by restating what we know: We are given (f∘g)(x)=8x3βˆ’20x2+22xβˆ’10(f \circ g)(x) = 8x^3 - 20x^2 + 22x - 10 and g(x)=2xg(x) = 2x. In this case, g(x)=2xg(x) = 2x is our inner function. This is the function we apply first. The other, 8x3βˆ’20x2+22xβˆ’108x^3 - 20x^2 + 22x - 10 represents the composite function. This is the result of applying ff to the output of gg. Identifying these two is a critical first step. It provides the foundation we need to determine f(x)f(x). Let's replace g(x)g(x) in the composite function. Let u=g(x)u = g(x), therefore u=2xu = 2x. Now, we want to rewrite 8x3βˆ’20x2+22xβˆ’108x^3 - 20x^2 + 22x - 10 in terms of uu. The goal here is to express everything in terms of u=2xu = 2x. Since we know u=2xu = 2x, it follows that x = rac{u}{2}. The next part is to substitute this value into the composite function.

Step 2: Substitution and Transformation

Here’s where the magic begins! We need to rewrite (f∘g)(x)(f \circ g)(x) in terms of g(x)g(x). Since we know g(x)=2xg(x) = 2x, we can substitute 2x2x in place of every xx in the equation 8x3βˆ’20x2+22xβˆ’108x^3 - 20x^2 + 22x - 10. However, we are not directly substituting the values of xx. Instead, we substitute x = rac{u}{2} into the composite function. Doing this transforms the expression into one that involves uu. Let's start with the substitution: 8( rac{u}{2})^3 - 20( rac{u}{2})^2 + 22( rac{u}{2}) - 10. Simplifying this, we get 8( rac{u^3}{8}) - 20( rac{u^2}{4}) + 22( rac{u}{2}) - 10. Then, further simplifying, we have u3βˆ’5u2+11uβˆ’10u^3 - 5u^2 + 11u - 10. This simplified expression is what the composite function becomes when expressed in terms of uu. The transformation we have performed allows us to focus on how f acts on uu. This is the crux of the problem. We have successfully replaced xx with uu, which directly relates to g(x)g(x). This means we are now working with f(u)f(u), where uu is the output of gg. The transformation process requires careful attention to detail. Double-checking each step ensures that the final result is accurate. Now that we have transformed the composite function in terms of uu, we can now express f(u)f(u) more directly.

Step 3: Expressing f(u)

From the previous step, we've transformed the composite function in terms of uu. We have: (f∘g)(x)=u3βˆ’5u2+11uβˆ’10(f \circ g)(x) = u^3 - 5u^2 + 11u - 10, where u=2xu = 2x. Because uu is essentially the output of g(x)g(x), we can now write f(u)=u3βˆ’5u2+11uβˆ’10f(u) = u^3 - 5u^2 + 11u - 10. This step is a direct result of our substitution in the previous step. We are now in the home stretch, we know how ff behaves on its input, which in this case, is uu. We can now replace uu with xx because the variable name doesn't really matter. We could call it tt, zz, or anything else. The function's behavior remains the same. The process is now complete, and we have successfully found f(x)f(x). It's important to understand what we've done here. We've untangled the composite function to reveal the inner workings of ff. We have essentially "undone" the composition, allowing us to see ff in isolation. This step completes the calculation and gives us the final function, ready for use. Understanding this step will also allow you to solve more complex problems with ease. Let's go through the steps to summarize the process.

Conclusion: The Answer Revealed!

To recap: We began with (f∘g)(x)(f \circ g)(x) and g(x)g(x) and wanted to find f(x)f(x). We learned that function composition combines two functions where the output of one becomes the input of another. By understanding this, we identified g(x)=2xg(x) = 2x as our inner function. We transformed the composite function by substituting xx in terms of uu (u=2xu = 2x). This gave us an expression in terms of uu, which allowed us to identify the form of ff. Finally, after simplifying, we successfully determined f(x)f(x). Therefore, f(x)=x3βˆ’5x2+11xβˆ’10f(x) = x^3 - 5x^2 + 11x - 10.

Final Answer:

f(x)=x3βˆ’5x2+11xβˆ’10f(x) = x^3 - 5x^2 + 11x - 10

Congratulations, you did it! You’ve successfully untangled the function composition and discovered the function f(x)f(x). This is a fantastic achievement. Remember that the key is to approach each problem with a clear understanding of the concepts and a step-by-step method. You are now equipped with the knowledge and tools needed to tackle similar problems in the future. Keep practicing, and you'll find that function composition becomes second nature. Great job, and happy problem-solving!

Additional Tips and Tricks

  • Practice, practice, practice! The more you work with function composition, the more comfortable you'll become. Try different examples and vary the complexity of the functions.
  • Break it down. Don't be afraid to take things one step at a time. The problem might seem daunting initially, but breaking it down into smaller, manageable steps makes it much easier to solve.
  • Check your work. Always double-check your calculations, especially when simplifying expressions. This helps to avoid careless errors.
  • Use visual aids. Sometimes, drawing diagrams or using graphs can help you visualize the function composition process.
  • Understand the concept. Make sure you understand the underlying concepts of function composition. This will help you solve different types of problems, not just the ones that look exactly like the example.

Remember, learning mathematics is a journey. Keep exploring, keep practicing, and most importantly, keep having fun!