Matching Quadratic Equations With Solution Sets
Hey guys! Let's dive into the exciting world of quadratic equations! In this article, we're going to match each quadratic equation with its correct solution set. This is a fundamental skill in algebra, and by the end of this guide, you'll be a pro at solving these equations and matching them to their solutions. So, grab your pencils, and let's get started!
Understanding Quadratic Equations
Before we jump into matching equations with solutions, let's make sure we're all on the same page about what a quadratic equation is. Quadratic equations are polynomial equations of the second degree. This means the highest power of the variable (usually 'x') is 2. The general form of a quadratic equation is:
ax² + bx + c = 0
Where 'a', 'b', and 'c' are constants, and 'a' is not equal to 0. The solutions to a quadratic equation are the values of 'x' that make the equation true. These solutions are also known as roots or zeros of the equation.
Methods for Solving Quadratic Equations
There are several methods to solve quadratic equations, and knowing these methods is crucial for matching equations with their solution sets. Here are the primary techniques:
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Factoring: This method involves breaking down the quadratic expression into the product of two binomials. If you can factor the equation, you can easily find the solutions by setting each factor equal to zero.
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Completing the Square: This method involves manipulating the equation to form a perfect square trinomial. It's a bit more involved than factoring but works for any quadratic equation.
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Quadratic Formula: This is the most versatile method, as it can solve any quadratic equation. The quadratic formula is:
x = (-b ± √(b² - 4ac)) / 2a
Where 'a', 'b', and 'c' are the coefficients from the general form of the quadratic equation.
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Using the Square Root Property: This method is particularly useful when the equation is in the form x² = k, where k is a constant. You simply take the square root of both sides to find the solutions.
In this article, we'll use a combination of these methods to solve the given equations and match them with their solution sets.
Matching the Equations with Solutions
Now, let's get to the main task: matching the given quadratic equations with their solution sets. We have the following equations:
- 2x² - 32 = 0
- 4x² - 100 = 0
- x² - 55 = 9
- x² - 140 = -19
- 2x² - 18 = 0
We'll solve each equation step by step and then determine the solution set.
1. Solving 2x² - 32 = 0
Let's start with the first equation: 2x² - 32 = 0. To solve this, we can use a combination of algebraic manipulation and the square root property.
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Step 1: Isolate the x² term.
Add 32 to both sides of the equation:
2x² = 32
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Step 2: Divide by the coefficient of x².
Divide both sides by 2:
x² = 16
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Step 3: Take the square root of both sides.
Remember to consider both positive and negative roots:
x = ±√16
x = ±4
So, the solution set for the first equation is {-4, 4}.
2. Solving 4x² - 100 = 0
Next, let's tackle the second equation: 4x² - 100 = 0. We'll use a similar approach to the first equation.
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Step 1: Isolate the x² term.
Add 100 to both sides:
4x² = 100
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Step 2: Divide by the coefficient of x².
Divide both sides by 4:
x² = 25
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Step 3: Take the square root of both sides.
Remember to consider both positive and negative roots:
x = ±√25
x = ±5
The solution set for the second equation is {-5, 5}.
3. Solving x² - 55 = 9
Now, let's solve the third equation: x² - 55 = 9. This one is also straightforward using the square root property.
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Step 1: Isolate the x² term.
Add 55 to both sides:
x² = 9 + 55
x² = 64
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Step 2: Take the square root of both sides.
Remember to consider both positive and negative roots:
x = ±√64
x = ±8
The solution set for the third equation is {-8, 8}.
4. Solving x² - 140 = -19
Let's move on to the fourth equation: x² - 140 = -19. This one follows the same pattern as the previous equations.
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Step 1: Isolate the x² term.
Add 140 to both sides:
x² = -19 + 140
x² = 121
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Step 2: Take the square root of both sides.
Remember to consider both positive and negative roots:
x = ±√121
x = ±11
The solution set for the fourth equation is {-11, 11}.
5. Solving 2x² - 18 = 0
Finally, let's solve the fifth equation: 2x² - 18 = 0. This equation is similar to the first two we solved.
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Step 1: Isolate the x² term.
Add 18 to both sides:
2x² = 18
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Step 2: Divide by the coefficient of x².
Divide both sides by 2:
x² = 9
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Step 3: Take the square root of both sides.
Remember to consider both positive and negative roots:
x = ±√9
x = ±3
The solution set for the fifth equation is {-3, 3}.
Summary of Solution Sets
Now that we've solved each equation, let's summarize the solution sets:
- 2x² - 32 = 0: {-4, 4}
- 4x² - 100 = 0: {-5, 5}
- x² - 55 = 9: {-8, 8}
- x² - 140 = -19: {-11, 11}
- 2x² - 18 = 0: {-3, 3}
Matching these solutions with the original equations completes our task. We've successfully navigated through the process of solving quadratic equations and identifying their solution sets. This skill is essential for further studies in algebra and beyond.
Tips for Solving Quadratic Equations
Solving quadratic equations can become second nature with practice. Here are a few tips to keep in mind:
- Always simplify the equation as much as possible before choosing a method to solve it. This might involve combining like terms or factoring out a common factor.
- Consider the structure of the equation. If it's in the form x² = k, the square root property is the quickest way to solve it. If it's easily factorable, that might be the simplest approach.
- Don't forget the ± sign when taking the square root. Quadratic equations often have two solutions.
- If you're stuck, the quadratic formula is your best friend. It works for any quadratic equation, no matter how complex.
- Practice, practice, practice! The more you solve quadratic equations, the better you'll become at recognizing patterns and choosing the most efficient solution method.
Real-World Applications of Quadratic Equations
You might be wondering, "When will I ever use quadratic equations in the real world?" Well, the truth is, quadratic equations pop up in many different fields, from physics to engineering to economics. Here are a few examples:
- Physics: Projectile motion, like the trajectory of a ball thrown in the air, can be modeled using quadratic equations. They help us calculate how high the ball will go and how far it will travel.
- Engineering: Quadratic equations are used in designing structures, such as bridges and buildings. They help engineers calculate the stresses and strains on materials.
- Economics: Quadratic equations can be used to model supply and demand curves, helping economists understand market behavior.
- Computer Graphics: Quadratic equations are used in creating curves and surfaces in 3D graphics, making your favorite video games and animated movies possible.
- Optimization Problems: Many optimization problems, where we want to find the maximum or minimum value of something, involve quadratic equations.
Understanding quadratic equations gives you a powerful tool for solving problems in various fields. It’s not just an abstract concept; it has practical applications that shape the world around us.
Conclusion
So, there you have it! We've successfully matched each quadratic equation with its solution set. We started by understanding what quadratic equations are and the various methods for solving them. Then, we methodically solved each equation, found its solutions, and matched them correctly. We also looked at some tips for solving quadratic equations and explored their real-world applications.
Remember, guys, math is like a puzzle, and quadratic equations are just one piece of the puzzle. The more you practice and understand the concepts, the easier it becomes to solve these puzzles. Keep up the great work, and you'll be a quadratic equation master in no time!
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